In column-I condition on velocity, force and acceleration of a particle is given. Resultant motion is described in column-II. 
= instantaneous velocity –
Column-I | Column-II |
(i) × = 0 and = Constant | [A] path will be circular path |
(ii) . = 0 and = Constant | [B] speed will increase |
(iii) = 0 all the time and = constant and the particle always remains in one plane | [C] path will be straight line |
(iv) = 2 – 3 and acceleration at all time | [D] path will be parabolic |
Text Solution
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Ans.
(i) [C]
(ii) [B]
(iii) [A]
(iv) [B, C]
Sol. (i) 
= constant and 
= 0
Therefore initial velocity is either in direction of constant force or opposite to it. Hence the particle will move in straight line and speed may increase or decrease.
(ii) 
= 0 and 
= constant
Initial velocity is perpendicular to constant force, hence the path will be parabolic with speed of particle increasing.
(iii) 
= 0 means instantaneous velocity is always perpendicular to force. Hence the speed will remain constant. And also 
= constant. Since the particle moves in one plane, the resulting motion has to be circular.
(iv) 
= 2 
– 3 
and 
= 6 
– 9 
. Hence initial velocity is in same direction of constant acceleration, therefore particle moves in straight line with increasing speed.
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